1/2 ? |
I think it is less than 1/2. The first two points can be anywhere, but the third one must be on an arc that is less than 1/2 of the circle. The actual number probably needs an integration. |
我是这样想的,先通过第一点画一条直径,然后另两点或者在直径的同一侧(钝角三角形),或者在两侧(锐角三角形), 概率各1/2. 这样想有漏洞吗? |
The problem is that when 另两点在直径的两侧, it may still be a 钝角三角形 |
I see, thank you! |
1/4 ? |
3/4-- Assume the tree points are randomly sampled from a circle. |
1/4 is right. area of triangle |
设 A,B为第一,二点,弧 AB 是小于半圆那段弧,AA',BB' 是直径,第三点C只有落在弧 A'B' 上,才得锐角三角形。因为 B' 出现在半圆上任何点的机率是均等的,所以C出现在弧 AB' 和 A'B'上的平均概率相同,而C出现在半圆上的概率是1/2,所以出现在 A'B' 上的平均概率是1/4。可以这样想吗? |
Good thinking. I was thinking about the length od A'B', and need to do an integration to have 1/4. |
X,Y各取PI & 2PI点, PI-PI / 2PI-2PI 连线 按几何概率得:3/4 |
It depends on the definition of randomness. By assuming different random models (events of equal probabilities), we can arrive at different answers. |
你的意思是,这个问题跟任画一弦大于半径的那个问题有异曲同工之处? |
let A be (1,0) (polar coordinates) B=(1,b) , b takes any value in (0,Pi) for a given B=(1,x), C=(1,c), c is then only allowed in (Pi,Pi+x). integral x/(2*Pi) from 0 to Pi is Pi/4. 赶快更正 is right. |
What are you guys doing? Didn't you realize that you need to divided your result by the length of the interval? |
sorry, forgot to divide it by 2---because b takes value in (0,Pi), just . So eine Schweinerei :( |
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