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A triangle ABC. Line AD divide equally the angle BAC, i.e., BAD = CAD Line AE divide equally heline BC, i.e., BE=CE From E, make a line EF perpendicular to line AD. cross point F, i.e. From F, make a line FG paralell to Line AB, cross line AE with G Connect point B G and extend to cross AC with H Proof AH = HC
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