One way to handle (1,2,3,4,5):
1, 2, 3, 4, 5
1, 3, 3, 4, 5
1, 3, 2, 4, 8
2, 4, 2, 4, 8
0, 4, 4, 4, 8
4, 4, 4, 4, 8
0, 8, 0, 8, 8
8, 8, 8, 8, 8
if we assume there is a solution and work backward, we will see that the result number must be in the form of 2^N provided that the 5 initial numbers are different.
ie if we got x,x,x,x,x as the final line,
By working backward, we have
0,x,x,x,x,
x/2,x/2,x,x,x or 0,0,x,x,x
...
I don't know if there is a solution for any sets of 5 numbers.
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哈哈哈哈 O(∩_∩)O哈哈~ 好久不来了，不小心看了一眼自己主页，发现自动关联了自己以往发过的帖，点进这个看了一眼，笑个半死。。。敢情我当初还发过这么搞笑的东西啊，我自己完全不记得了 
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发表于 2005-1-10 07:17:09
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