试仅用圆规和直尺画出“七点问题” http://www.topchinesenews.com/readpost.aspx?topic_id=9&msg_id=8548&level_string=0&page=1的解。
1. 作点A, B间距记作1 2. 分别以A, B为圆心, 以1为半径作弧, 相交于C,D 3. 以C为圆心, 以CD为半径作弧DE, 以D为圆心以1为半径作弧CE, E为两弧的一个交点. 4. 分别以C, E为圆心, 以1为半径作弧, 相交与F, G A,B,C,D,E,F,G即为所求的七点. 咦, 我的直尺呢? |
“弧CE”似应为“弧AE”或“弧BE”. |
谢谢指正 |
1. 作点A, B间距记作1 2. 分别以A, B为圆心, 以1为半径作弧, 相交于C,D 3. 以C为圆心, 以CD为半径作弧DE, 以D为圆心以1为半径作弧CE, E为两弧的一个交点. 4. 分别以C, E为圆心, 以1为半径作弧, 相交与F, G A,B,C,D,E,F,G即为所求的七点. 咦, 我的直尺呢? “弧CE”似应为“弧AE”或“弧BE”.
Using your method, I produced the graphic that appears below (six right triangles). I don't think that this is correct. Where did I go wrong? I would appreciate your comments on this. Please include a graph if possible.
0C 0G
0A 0B 0E
0D 0F
|
I finally got it! Thank you very much for taking the time to post the superb grephic. |
欢迎光临 珍珠湾ART (http://zzwav.com/) | Powered by Discuz! X3 |