珍珠湾ART

标题: Another prob question [打印本页]

作者: HF:    时间: 2008-7-19 00:47
标题: Another prob question

Toss a coin until the nth Head turns up. Let Y=number of required tosses
, calculate Prob(Y is even).  Assume the probability of head of each toss is p.
www.ddhw.com

 

作者: try-it-    时间: 2008-7-24 18:52
标题: 回复:Another prob question

let
O (n) be the total probability of nth head shows up at the odd number of tosswww.ddhw.com
E (n) for even number of toss  
we have
E (n) = (1-p) * O (n) + p * O (n-1)
E (n) + O (n) = 1
 thus we get a recurrence relation for O (n)
O (n) = -p/(2-p) * O (n-1) + 1/(2-p)
 
Solving it we have
O (n) = (-p/(2-p))^(n-1) * ( O (1) - 1/2) +1/2
with O( 1 ) = 1/(2-p)


 





欢迎光临 珍珠湾ART (http://zzwav.com/) Powered by Discuz! X3