n = 4k+1, k = 0,1,2,... |
当n是什么数的时候,下列合式可以被4整除? 1n + 2n +3n +4n 本贴由[salmonfish]最后编辑于:2007-11-9 16:45:49 |
我这儿还没出完题呢,你那儿解都出来了。只好换汤不换药了。 本贴由[salmonfish]最后编辑于:2007-11-9 16:41:21 |
Any odd. |
any k and 2k. k is odd. |
in other words, only 4k is no good for it. And it is easy to show that 4k won't work. |
You are right. I mis-calculated one of the cases. |
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