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标题: 称重问题 [打印本页]

作者: ob    时间: 2006-4-13 09:41
标题: 称重问题

车间主任给小王一个样本零件,让小王照该零件加工14个同样的零件。已知这14个加工好的零件中有且仅有一个零件的重量不对(不知轻重),又知最后加工的一个零件肯定不会偏重,请问,你能用天平只称3次,就肯定可以帮小王找出问题零件,并告诉他轻重吗?
www.ddhw.com

 

作者: 喝醉了的猫    时间: 2006-4-13 13:26
标题: ...10个的就超级难了...14个虽然多了一个参考...但觉得没可能

  ...10个的就超级难了...14个虽然多了一个参考...但觉得没可能





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作者: sean9991    时间: 2006-4-13 22:26
标题: 回复:称重问题

I guess you mean 13 parts in this problem.  It's a well known fact that without the extra condition, there is one scenario (for 13 parts problem) we can't tell if the defect is heavier or lighter.  This extra condition helps to tell the weight of the defect.  If your problem has a solution, doesn't it imply we can identify the weight for 13 parts? 


 





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