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标题: 美国奥赛题(1981) 试问这个县至少有几个区? [打印本页]

作者: 野 菜 花    时间: 2005-2-26 21:05
标题: 美国奥赛题(1981) 试问这个县至少有几个区?

某个县下属的每两个区都恰好由汽车,火车,飞机三种交通方式中的一种直接联系。已知在全县中三种交通方式全有,但没有一个区三种方式全有,并且没有三个区中两两联系的方式完全相同。试问这个县至少有几个区?

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作者: 乱弹    时间: 2005-2-26 21:50
标题: 4 at most, 3 at least. ???

I just have some rough idea, maybe I did not get the problem.
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作者: 野 菜 花    时间: 2005-2-26 21:55
标题: 抱歉,是问至多有几个区。

  抱歉,是问至多有几个区。





作者: 野 菜 花    时间: 2005-2-26 21:58
标题: Right! You have good sence at math. Can you prove?

4 is possible, 5 is not possible.
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作者: 乱弹    时间: 2005-2-26 22:30
标题: 回复:Right! You have good sence at math. Can you pro

We can draw a graph to represent the problem.


Vertex: town. Edge: transportation. (Red: car,yellow: train, blue: plane)

We can not have a triangle of the same color, or a vertex that has three kinds of outgoing edges

First, we have the following claim:www.ddhw.com

For each vertex, at most two outgoing edges are of the same color.

Proof:If the edges from vertex A to B, C and D are of the same color, say red, then since the edges between any two of B, C, D must be blue or yellow (or we get a red triangle) , but since we can not have a vertex that has three kinds of outgoing edges, for B, C and D, there is only one choice beside red for the color of outgoing edges, we must get a triangle BCD of the same color. www.ddhw.com

 Because of the claim, 6 or above is not OK.

 Now prove 5 is not OK. The following is what I think is the simplest.

 Because of the claim, if 5 is OK, then for each vertex, there are exactly two kinds of outgoing edges, say two red, two yellow. The we have a few cycles of edges with the edges in each cycle of the same color. There are at least three cycles, and each cycle has a length of at least 4, then we will have at least 12 edges. But we only have 10

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作者: 野 菜 花    时间: 2005-2-27 02:03
标题: 厉害!佩服![:B][@};-]

  厉害!佩服!









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