101, 10101, 1010101, 101010101, ...
问在这串数中有多少个质数?并请证明你的结论
Only 1. We know 101 is prime. For any other (call it n), n * 11 = 11....11 (2k 1's for some k > 2) = 11...11 * 100...001.(First factor contains k 1's, second k-1 0's.) Now one of them is divisible by 11, and the other devides n. |
Thanks for the question. It gave me the idea to solve this problem in WXC: The repeat of a positive integer is obtained by writing it twice in a row (so, for example, the repeat of 254 is 254254). Is there a positive integer whose repeat is a perfect square? |
Could you explain more? We need to show a factor in n. I do not see your reason for it. |
it here as 加 新 贴 ? |
All right. I did not because I thought people here like only the quick-wit type of problems. |
101一个 |
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