P = 1 - P(365,50)/365^50 = 1 - 365!/315!/365^50 = 1 - 0.029626 = 0.970374 P(365,50) is the permutation of all possible ways to distribute 50 b-days. (no repeat) 365^50 represent all possible ways of arranging 50 bdays. and you will get the probability of more than 1 ppl has the same bday. then subtracted by 1, u will get the answer :D |
you forgot if somebody was born in leap year, then his birthday is Feb 29. And the probability of a random people has this birthday is approximately 97/400 of other days. |
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